994A - Fingerprints - CodeForces Solution


implementation *800

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Python Code:

n,m=map(int,input().split())
val=input()
keys=val.split()
u=input()
fp=u.split()
for i in range(n):
    if(keys[i] in fp):
        print(keys[i],end=" ")

C++ Code:

#include<bits/stdc++.h>
using namespace std;
int main(){
int n,m,i,j,a[10001],b[10001];
cin>>n>>m;
for(i=0;i<n;i++){
    cin>>a[i];
}
for(i=0;i<m;i++){
    cin>>b[i];
}
vector<int>v;
for(i=0;i<n;i++){
    for(j=0;j<m;j++){
        if(a[i]==b[j]){
            v.push_back(a[i]);
        }
    }

}
for(i=0;i<v.size();i++){
    cout<<v[i]<<" ";
}
return 0;
}


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